HCL vs CA

Could only measure the CLO2 concentration in ppm. A photometer was used. Setup was 3 drop doses at different times then into 120ml distilled water, then measure.

JB13

If a photometric was used, a blank solution of HCL + H20 should be use to zero the equipment. If was the photometric that only have one sample reading will produce the reading that you see in the graph that have more concentration per time compare with the same mixture with Citric Acid. The same apply to Citric acid a blank solution has to be use in order to eliminate any reading that belong to the mixture of Citric acid and water. That way is demostrated that other component use in the solution does not affect the reading.

Tomas tells me there is a group in Europe who are using yet another activator, sodium hydrogen sulfate to activate SC. They are using it to make CDH. One of the European users of sodium hydrogen sulfate is Pavel Eiselt, a friend of Jim's. A concern that Tomas has is that the results of using sodium hydrogen sulfate may be too good; apparently all of the SC is reacted with this activator. Scott and I wanted to leave about 50% of the SC unreacted so it could be used by the body similar to classic MMS, except CDH is more activated than MMS.

People here have realized that CDH should contain certain unreacted portion of SC and now looking for the right amount of sodium hydrogen sulfate (sodium bisulfate). Responses to CDH with this activator have been very positive (taste, tolerability and therapeutic effect).

FYI

For those chemist that are reading about HCL 4%, is not a 4% solution is a 4 Molar solution. Dont get confuse. Like I was until i find out the threat where somebody explain how to make the 4% solution starting from the 35 Molar solution that we normally get from the Chemical distributor.

If you take 4 ml of the concentrate and disolve to 100 ml matrax the resulting solution will be 1.4 Molar or 1.4 mol/liter and the 4% solution is 4 Mol/Liter base on the threat how the CDH is made.

People you not helping MMS with those calculation. Maybe a person that did not know Chemistry will pass but there a lot of proffesional that read this threat and leave because they only need one reason o defect to run away. I really believe in the product, but there so many variation from the original method of Jim Humble. I undertand that they are trying to make the MMS more easy to drink and other have some economical interest that does not want other know the formula how to make MMS to sale. But for a good Chemist no going to take long to find out the true about your mix. Chlorite determination is one of the first analysis that we learn in the lab of analytical chemistry.

gjplaceres wrote:

For those chemist that are reading about HCL 4%, is not a 4% solution is a 4 Molar solution. Dont get confuse. Like I was until i find out the threat where somebody explain how to make the 4% solution starting from the 35 Molar solution that we normally get from the Chemical distributor.

I can not agree. The HCl solution that we normally get from the chemical distributor is about 36 % (w/w), that is 360 grams of HCl in 1000 grams of solution, or 424 grams in 1000 ml of solution. Its molarity is 11.64 mol/l. No 35 molar hydrochloric acid exists! Please see eg. en.wikipedia.org/wiki/Hydrochloric_acid

Tomas

Thank you for the link.

Well if more confuse now because is using a program design for Molarity using percent.

So they take 50 ml of the 11.64 mol/l solution that is equal to .582 Mol then dilute in .4375 lt = 1.33 Mol/Lt solution. if I take 4 ml of the concentrate to (36%) = 11.64 mol/l that have .04656 mol and dilute in .1 liter
will be equal to .04656 Mol X 36.5 gram/Mol = 1.6994 gram of HCL in 100 ml of water W/W will be 1.67% No 4%

11.64/1000 = X/50 X = .582 Mol dilute in .4375 lt = 1.33 mol/lt or 1.33 Molar

11.64/1000 = X/4 X = .04656 Mol dilute in .1 lt = .4656 Mol/lt or .4656 Molar solution

if one mol of HCL = 36.5 grams the total grams in the 50 ml solution from concentrate = 21.243of HCL those was disolve in 387.5 grams of Water, then 387.5g + 21.243g =. 21.243/408.743= .05197 X 100 = 5.197% (W/W)

So still did not get 4% label

This is the picture that bring the previous posting.