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the Ag+ and clo2
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17 Aug 2020 06:03 #65563
by ojrain
the Ag+ and clo2 was created by ojrain
Hello, I want know the Ag+ and ClO2 can react to form compounds ?
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18 Aug 2020 15:35 #65581
by paul
Replied by paul on topic the Ag+ and clo2
Yes. clo2 oxidizes ALL metals to soluble salts thus neutralising both.
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19 Aug 2020 09:06 - 19 Aug 2020 09:09 #65587
by ojrain
Replied by ojrain on topic the Ag+ and clo2
I want to know what will be generated,,Agcl or Ago?
I mixed them and did not see any precipitation
My friend has a very good treatment effect with Ag+. (not Ag)
It would be great if it can not conflict with clo2
I mixed them and did not see any precipitation
My friend has a very good treatment effect with Ag+. (not Ag)
It would be great if it can not conflict with clo2
Last edit: 19 Aug 2020 09:09 by ojrain.
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20 Aug 2020 05:28 - 20 Aug 2020 05:49 #65597
by paul
Replied by paul on topic the Ag+ and clo2
neither it seems;
1 decade ago
Favorite Answer
Oxidation half-reaction:
Balance the main atom (Cl).
It's already balanced in this reaction.
ClO2^- ---> CIO4^-
In an acid solution:
First, balance O by adding H2O.
ClO2^- + 2H2O ---> CIO4^-
Second, balance H by adding H+.
ClO2^- + 2H2O ---> CIO4^- + 4H^+
Now, add e- to the more positive side of the
equation, to balance charge on each side.
ClO2^- + 2H2O ---> CIO4^- + 4H^+ + 4e^-
Reduction half-reaction:
Balance the main atom (Ag).
It's already balanced in this reaction.
Ag^+ ---> Ag
Now, add e- to the more positive side of the
equation, to balance charge on each side.
Ag^+ + 1e^- ---> Ag
To make the number of e- gained and lost equal,
multiply the first equation by 1 and the second by 4.
1 x (ClO2^- + 2H2O ---> CIO4^- + 4H^+ + 4e^-)
4 x (Ag^+ + 1e^- ---> Ag)
==>
ClO2^- + 2H2O ---> CIO4^- + 4H^+ + 4e^-
4Ag^+ + 4e^- ---> 4Ag
Finally, add the two half reactions together,
simplifying the number of H2O and H+.
...4Ag^+ + 4e^- ---> 4Ag
+ ClO2^- + 2H2O ---> CIO4^- + 4H^+ + 4e^-
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
4Ag^+ + ClO2^- + 2H2O ---> 4Ag + CIO4^- + 4H^+
the result is solid silver , perchlorate and hydrogen gas, none of which have a charge for destroying pathogens. Probably best to choose one protocol or the other but don't mix.
1 decade ago
Favorite Answer
Oxidation half-reaction:
Balance the main atom (Cl).
It's already balanced in this reaction.
ClO2^- ---> CIO4^-
In an acid solution:
First, balance O by adding H2O.
ClO2^- + 2H2O ---> CIO4^-
Second, balance H by adding H+.
ClO2^- + 2H2O ---> CIO4^- + 4H^+
Now, add e- to the more positive side of the
equation, to balance charge on each side.
ClO2^- + 2H2O ---> CIO4^- + 4H^+ + 4e^-
Reduction half-reaction:
Balance the main atom (Ag).
It's already balanced in this reaction.
Ag^+ ---> Ag
Now, add e- to the more positive side of the
equation, to balance charge on each side.
Ag^+ + 1e^- ---> Ag
To make the number of e- gained and lost equal,
multiply the first equation by 1 and the second by 4.
1 x (ClO2^- + 2H2O ---> CIO4^- + 4H^+ + 4e^-)
4 x (Ag^+ + 1e^- ---> Ag)
==>
ClO2^- + 2H2O ---> CIO4^- + 4H^+ + 4e^-
4Ag^+ + 4e^- ---> 4Ag
Finally, add the two half reactions together,
simplifying the number of H2O and H+.
...4Ag^+ + 4e^- ---> 4Ag
+ ClO2^- + 2H2O ---> CIO4^- + 4H^+ + 4e^-
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
4Ag^+ + ClO2^- + 2H2O ---> 4Ag + CIO4^- + 4H^+
the result is solid silver , perchlorate and hydrogen gas, none of which have a charge for destroying pathogens. Probably best to choose one protocol or the other but don't mix.
Last edit: 20 Aug 2020 05:49 by paul.
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20 Aug 2020 12:05 #65600
by ojrain
Replied by ojrain on topic the Ag+ and clo2
It's so complicated. Thank you very much
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